Probability · KS3

Theoretical and Experimental Probability

If you flip a coin 100 times, will you get exactly 50 heads? Is your lucky dice really fair? How likely is a drawing pin to land point up, when there's no way to work it out on paper? This page shows two ways to find a probability, working it out and finding it by experiment, and why the second one gets better the more times you try.

National curriculum KS3: record, describe and analyse the frequency of outcomes of simple probability experiments involving randomness, fairness, equally and unequally likely outcomes, using appropriate language and the 0–1 probability scale; understand that the probabilities of all possible outcomes sum to 1

1 · Theoretical probability: what should happen

Some probabilities you can work out just by thinking. A normal dice has six faces, 1 to 6. If it's fair (not damaged or weighted), each face is just as likely to land on top as any other. We say the six results are equally likely.

A few words you'll need all the way through this page:

Outcome: one possible result. Rolling a dice has six outcomes: 1, 2, 3, 4, 5, 6.

Event: the thing you're interested in. It can be one outcome ("a six") or several ("an even number" = 2, 4 or 6).

Theoretical probability: the probability you work out, using equally likely outcomes, without doing any experiment.

When all the outcomes are equally likely, count them:

P(event) = number of favourable outcomes ÷ total number of outcomes

("Favourable" just means "the ones that count for your event".) You met this idea on the probability scale page. Tap the dice faces below to build an event, or pick one from the buttons.

Notice that theoretical probability tells you what is likely, not what will happen. P(six) = 1/6 does not mean "every sixth roll is a six". To see what really happens, we need to do an experiment.

2 · Experiments, trials and relative frequency

An experiment is something you do to collect results, like flipping a coin lots of times. Each single flip is called a trial. As you go, you count how many times each outcome happens. That count is the frequency (you might record it with a tally).

A frequency on its own doesn't tell you much. "I got 7 heads" sounds very different if you flipped 10 times or 1000 times. So we divide by the number of trials. This gives the relative frequency: the fraction of the trials on which the event happened.

relative frequency = frequency ÷ number of trials

Relative frequency is also called experimental probability, because it's a probability you find from an experiment. Like any probability it is between 0 and 1. Have a go: flip the coin and watch the table fill up.

The relative frequencies of heads and tails always add up to 1, because every flip was one or the other. (That's the same rule as P(not A) = 1 − P(A); see mutually exclusive outcomes.)

Showing the working. 7 heads in 12 flips: relative frequency = 7 ÷ 12 = 7/12 = 0.583 (to 3 d.p.). You can give a relative frequency as a fraction (simplify it if you can) or as a decimal. Always divide by the total number of trials, never by the number of tails.

3 · More trials, better estimates

Here is the big idea of this whole topic. Roll a fair dice and keep track of the relative frequency of sixes after every single roll. Theory says P(six) = 1/6 ≈ 0.167. Watch the orange line (your experiment) and the dashed teal line (theory).

Trials
Frequency
Relative freq.
Theory

Try several runs (press New run, and the old one turns grey). At the start, every run zig-zags wildly: one lucky six out of 3 rolls gives a relative frequency of 0.333, twice the theory. But as the number of trials grows, each run settles down close to the theoretical value. It never has to land exactly on it, but it gets closer and closer. Mathematicians call this the law of large numbers.

Same experiment, different groups

Imagine 30 groups in a school each flipping a coin. Does every group get the same relative frequency of heads? Choose how many flips each group does, then compare. Each dot is one group's result.

Lowest
Highest
Within 0.05 of 0.5

With 10 flips, results are spread right across the scale: some groups get 0.2 or 0.8 just by chance. With 1000 flips, every group lands very close to 0.5. Small experiments vary a lot; big experiments agree. That's why a scientist would never trust an estimate from only a handful of trials.

4 · When outcomes aren't equally likely

Drop a drawing pin (a thumb tack) on a table. It lands either point up (resting on its flat head) or point down (on its side, with the point touching the table). Are these equally likely? No! The shape of the pin makes one more likely, and there's no way to count "equally likely outcomes" to work it out. Theoretical probability can't help.

The only way is an experiment: drop it lots of times and use the relative frequency as an estimate of the probability. This pin has a secret probability chosen by the page. Drop it, then estimate P(point up).

The same idea works for real-world data. Insurance companies, weather forecasters and doctors all estimate probabilities from what happened before: relative frequency = number of times it happened ÷ number of times we looked. Practise with real-looking data:

Which method when?

5 · Is it fair? Spotting a biased dice

A dice (or coin, or spinner) is biased if some outcomes are more likely than others, for example because it's been weighted on one side. You can't tell by looking. But you can test it: roll it many times and compare each relative frequency with the 1/6 ≈ 0.167 that a fair dice should give.

First, make your own dice: drag the plum bars to make some faces more likely, then roll and see how the bias shows up. Then switch to mystery dice: the page secretly picks a fair or biased dice, and you decide from the evidence.

My verdict:

Three things to remember when you judge fairness:

6 · Expected frequency

Now turn the question round. If you know (or have estimated) a probability, how many times would you expect the event to happen in a certain number of trials? If P(six) = 1/6 and you roll 60 times, about one roll in every six should be a six, so you'd expect about 60 ÷ 6 = 10 sixes. That's the expected frequency:

expected frequency = probability × number of trials

Expected frequency is a prediction of what happens on average, not a promise. Rolling 60 times you might get 8 sixes, or 13. And it doesn't have to be a whole number: in 50 rolls you'd expect 50 × 1/6 = 8.33… sixes. Use the calculator, then press Do the trials to compare with a real (simulated) experiment.

Practice: expected frequency

Each question is new. If you go wrong, the feedback tries to spot which mistake you made.

7 · Common mistakes: streaks, "exactly half" and too few trials

Mistake 1: "It's due a six"

You've rolled a dice ten times and not seen a six. Surely a six is due now? No. A dice has no memory. Every roll is a fresh start, and P(six) is still 1/6. In the same way, after five heads in a row a fair coin is no more likely to land tails. Believing otherwise is called the gambler's fallacy (a fallacy is a mistaken belief), and it has cost gamblers a lot of money.

Test it yourself. The page flips thousands of coins, finds every time there was a streak of heads, and looks at what came next.

Mistake 2: "100 flips means exactly 50 heads"

Expected frequency of heads in 100 flips is 1/2 × 100 = 50. But how often do you get exactly 50? Make a prediction, then flip 100 coins many times and see how the totals spread out.

Sets of 100
Exactly 50
45 to 55
Last set

Exactly 50 heads happens only about 8% of the time (roughly 1 time in 12). But a result between 40 and 60 happens about 96% of the time. So 50 is the most likely single total, and results cluster round it, but "exactly 50" is unlikely. Getting 47 or 54 heads is no evidence at all that a coin is biased.

Common mistakes, all in one place

Worked examples

A coin is flipped 40 times and lands heads 22 times. Find the relative frequency of heads and of tails.
Frequencies: heads = 22. Tails = 40 − 22 = 18. Number of trials = 40.
Relative frequency of heads = frequency ÷ number of trials = 22 ÷ 40 = 22/40 = 11/20 = 0.55.
Relative frequency of tails = 18 ÷ 40 = 18/40 = 9/20 = 0.45.
Check: 0.55 + 0.45 = 1 ✓ (every flip was heads or tails).
Compare with theory: a fair coin has P(heads) = 0.5. 0.55 is a little more, but with only 40 flips that's a perfectly normal wobble. It is not evidence of bias.
A spinner with three equal sections (red, blue, green) is spun 100 times. Results: red 34, blue 51, green 15. Is it fair? How many blues would you expect in 500 spins?
Check the total: 34 + 51 + 15 = 100 ✓.
Relative frequencies: red 34 ÷ 100 = 0.34; blue 51 ÷ 100 = 0.51; green 15 ÷ 100 = 0.15. (Sum 0.34 + 0.51 + 0.15 = 1 ✓.)
Theory for a fair spinner: each colour 1/3 ≈ 0.333, so in 100 spins about 33 of each.
Compare: red (0.34) is close to 0.333, but blue (0.51) is far too high and green (0.15) far too low. With 100 spins these gaps are big, so the spinner seems to be biased towards blue. More spins would make us more sure.
Expected blues in 500 spins: because it seems biased, use the relative frequency, not 1/3. Expected frequency = 0.51 × 500 = 255.
Sam rolls a dice 120 times: 1 → 18, 2 → 21, 3 → 19, 4 → 20, 5 → 22, 6 → 20. Is the dice fair?
Check the total: 18 + 21 + 19 + 20 + 22 + 20 = 120 ✓.
Expected frequency for each face if fair: 1/6 × 120 = 120 ÷ 6 = 20.
Compare: every frequency is between 18 and 22, within 2 of the expected 20. As relative frequencies: 18 ÷ 120 = 0.15 up to 22 ÷ 120 = 0.183, all close to 1/6 ≈ 0.167.
Conclusion: there's no evidence that the dice is biased. The small differences are normal random variation.
Contrast: if the dice had been rolled 600 times and a six came up 180 times, that's 180 ÷ 600 = 0.3, nearly double 0.167, and 80 more than the expected 100. That would be strong evidence of bias.
A bag has 3 red, 5 blue and 2 green counters. A counter is taken and put back, 50 times. How many of each colour would you expect?
Total counters: 3 + 5 + 2 = 10, all equally likely to be picked.
Theoretical probabilities: P(red) = 3/10, P(blue) = 5/10 = 1/2, P(green) = 2/10 = 1/5.
Expected frequency = probability × number of trials:
red: 3/10 × 50 = 150 ÷ 10 = 15; blue: 1/2 × 50 = 25; green: 1/5 × 50 = 10.
Check: 15 + 25 + 10 = 50 ✓. (The colours are not equally likely, so it would be wrong to say 50 ÷ 3 of each.)
A bus company watched 250 journeys and the bus was late on 40 of them. Estimate P(late), and how many of the next 1200 journeys will be late.
Why relative frequency? "Late" and "on time" are not equally likely, so we use past data.
Estimate: P(late) ≈ 40 ÷ 250 = 40/250 = 4/25 = 0.16.
Expected late journeys: 0.16 × 1200 = 192.
How reliable? 250 journeys is a reasonable amount of data, so this is a sensible estimate, but the real number will be somewhere around 192, not exactly 192.

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