GCSE · Algebra

Inequalities and Regions

An equation has a few exact answers; an inequality usually has a whole range of them. "x is bigger than 3" is true for 3.1, 4, 100 and infinitely many other numbers. This page shows how to write, draw and solve inequalities, and (Higher) how to solve quadratic inequalities and shade regions on a graph.

GCSE subject content: solve linear inequalities in one variable; represent the solution set on a number line; Higher: solve linear inequalities in two variables and quadratic inequalities in one variable; represent the solution set using set notation and on a graph

Before you start. Solving an inequality uses the same "do the same to both sides" steps as solving a linear equation (see Linear equations). For the regions section you'll need to draw straight lines like y = 2x + 1 (see Linear graphs).

1 · Symbols and number lines

There are four inequality symbols. The open end of the symbol faces the bigger number, like a mouth eating it.

SymbolMeansExampleOn a number line
<is less thanx < 3open circle at 3, arrow left
≤is less than or equal tox ≤ 3filled circle at 3, arrow left
>is greater thanx > 3open circle at 3, arrow right
≥is greater than or equal tox ≥ 3filled circle at 3, arrow right

An open circle means the end number is not included (it's a strict inequality); a filled circle means it is included. Try the builder, then test yourself.

Which inequality does this number line show?

2 · Solving linear inequalities

To solve an inequality means to get x on its own, like solving an equation. You may add or subtract the same number on both sides, and multiply or divide both sides by a positive number, and the inequality stays true. There is one exception, and it's the whole point of this section:

multiply or divide by a negative → flip the sign

Why? 2 < 5 is true. Multiply both by −1: −2 and −5. But −2 is bigger than −5. Multiplying by a negative reflects every number in 0, so the order reverses. Slide k and watch the two plum numbers swap order.

Ways to avoid the flip. In 7 − 2x > 1 you can add 2x to both sides first: 7 > 1 + 2x, so 6 > 2x, so 3 > x, which is the same as x < 3. Either way, check with a number: x = 0 gives 7 > 1 ✓ and 0 < 3 ✓.

Never write the answer as an equation (x = 3) or forget which way it points. "3 > x" and "x < 3" say the same thing; read them carefully.

3 · Double inequalities and integer solutions

A double inequality like −2 < x ≤ 4 traps x between two values: bigger than −2 and at most 4. Solve it by doing the same thing to all three parts. An integer is a whole number (positive, negative or zero), and questions often ask you to list the integers that satisfy an inequality. Watch the ends: is each one included?

4 · Quadratic inequalities Higher

Set notation is a compact way to write a solution: {x : −2 < x < 3} reads "the set of all x such that x is between −2 and 3". For two separate pieces, write {x : x < −2} ∪ {x : x > 3} (∪ means "or", the union of the two sets).

To solve a quadratic inequality like x² − x − 6 < 0, never try to "solve it like an equation". Instead:

  1. Solve the equation x² − x − 6 = 0 to find the critical values (here x = −2 and x = 3).
  2. Sketch the graph y = x² − x − 6: a U shape crossing the x-axis at those values.
  3. "< 0" means "where is the curve below the x-axis?" That's between the roots. "> 0" means above: the two outside pieces.

Trap: x² < 9. It's tempting to write x < ±3, but that is meaningless. Sketch y = x² − 9: it is below the axis between −3 and 3, so −3 < x < 3. And x² > 9 is x < −3 or x > 3 (two separate inequalities, not one).

5 · Inequalities on a graph Higher

An inequality with two letters, like y > 2x − 1, is true for a whole region of the coordinate grid. The line y = 2x − 1 is the boundary. Every point above it has a bigger y, so satisfies y > 2x − 1; every point below doesn't.

Drag the plum test point around and watch the substitution.

6 · Regions from several inequalities Higher

When a question gives several inequalities, the region R that satisfies all of them is where all the shaded parts overlap. Draw each boundary line (solid or dashed), decide which side is wanted, and the region in the middle is usually a triangle or other polygon. Questions often ask you to list the integer points in R: points whose coordinates are both whole numbers. Points on a dashed boundary don't count; points on a solid one do.

Click every integer point inside R, then press Check.

Worked examples

Solve 3x + 5 < 20 and show the solution on a number line
Subtract 5: 3x < 15.
Divide by 3 (positive, so no flip): x < 5.
Number line: an open circle at 5 (5 is not included) with an arrow to the left.
Check: x = 4 gives 17 < 20 ✓; x = 5 gives 20 < 20, false ✓ (so 5 is correctly excluded).
Solve 7 − 2x ≥ 1
Subtract 7: −2x ≥ −6.
Divide by −2 and flip the sign: x ≤ 3.
Check with x = 0: 7 ≥ 1 ✓ and 0 ≤ 3 ✓. With x = 4: −1 ≥ 1 is false ✓, and 4 ≤ 3 is false ✓.
List the integers n with −3 < 2n + 1 ≤ 9
Subtract 1 from all three parts: −4 < 2n ≤ 8.
Divide all three parts by 2: −2 < n ≤ 4.
List: −2 is not included (strict), 4 is included. n = −1, 0, 1, 2, 3, 4.
Find the smallest integer x with 5x − 2 > 2x + 7
Subtract 2x: 3x − 2 > 7. Add 2: 3x > 9. Divide by 3: x > 3.
Smallest integer: 3 itself is not allowed (strict), so x = 4.
Solve x² − 2x − 15 ≤ 0, giving your answer in set notation Higher
Critical values: x² − 2x − 15 = 0 → (x − 5)(x + 3) = 0 → x = 5 or x = −3.
Sketch: a U-shaped curve crossing the x-axis at −3 and 5.
≤ 0 means on or below the axis: between the roots, including them.
Answer: −3 ≤ x ≤ 5, or {x : −3 ≤ x ≤ 5}.
Solve x² > 16 Higher
Critical values: x² = 16 → x = −4 or x = 4.
Sketch y = x² − 16: above the axis outside the roots.
Answer: x < −4 or x > 4, i.e. {x : x < −4} ∪ {x : x > 4}. Not "x > ±4".
Exam-style: list the integer points (x, y) satisfying y ≥ 1, x + y < 6 and y ≤ 2x Higher
Draw the boundaries: y = 1 (solid), x + y = 6 (dashed), y = 2x (solid).
Wanted sides: above y = 1; below x + y = 6 (test (0, 0): 0 < 6 ✓); below y = 2x (test (1, 0): 0 ≤ 2 ✓).
Row by row: y = 1: x = 1, 2, 3, 4 (x = 5 is on the dashed line, excluded). y = 2: x = 1, 2, 3. y = 3: x = 2 (x = 1.5 is the edge). y = 4: none.
Answer: (1, 1), (2, 1), (3, 1), (4, 1), (1, 2), (2, 2), (3, 2), (2, 3): 8 points.

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