Probability · KS3

Sample Spaces and Venn Diagrams

Before you can work out a probability, you need to know everything that could happen. This page shows you how to list outcomes so you never miss one, how to use grids for two dice, how to read and complete two-way tables, and how to sort things into Venn diagrams, then turn all of them into probabilities.

National curriculum KS3: enumerate sets and combinations of sets systematically, using tables, grids and Venn diagrams; generate theoretical sample spaces for single and combined events with equally likely, mutually exclusive outcomes and use these to calculate theoretical probabilities

1 · Outcomes, events and sample spaces

Flip a coin. What could happen? It could land heads or tails. That's it. Each possible result is called an outcome. Doing the thing once (one flip, one roll, one spin) is called a trial.

The list of every possible outcome is called the sample space. We often write it inside curly brackets: for a coin it is { H, T }, and for an ordinary six-sided dice it is { 1, 2, 3, 4, 5, 6 }.

An event is the thing you're interested in: "roll an even number", for example. An event is made of one or more outcomes; "even" is the outcomes 2, 4 and 6. When all the outcomes are equally likely (a fair coin, a fair dice), the probability of an event is

P(event) = outcomes in the event ÷ all outcomes

You met this on the probability scale page. The whole point of a sample space is to get the bottom number right. Pick an experiment below, then tap outcomes (or use a ready-made event) to see the probability.

Sample space
Event
Probability

Two key words. An event with no outcomes in it (like "roll a 7") is impossible: P = 0. An event containing every outcome (like "roll less than 7") is certain: P = 1.

2 · Listing outcomes for two things at once

Now flip a coin and roll a dice. An outcome is now a pair, like (H, 3): heads on the coin and 3 on the dice. How many pairs are there? If you write them down in a random order you'll almost certainly miss some or write some twice. The trick is to be systematic (work in a fixed order):

  1. Fix the first thing at its first outcome (H).
  2. Run through every outcome of the second thing: (H, 1), (H, 2), …, (H, 6).
  3. Move the first thing on (T) and run through the second thing again.

Choose two items and press Next outcome to build the list one step at a time. Each row of the grid is one outcome of the first item.

Notice the pattern: a coin has 2 outcomes and a dice has 6, and the grid has 2 rows of 6, so there are 2 × 6 = 12 outcomes. In general, multiply the numbers of outcomes (don't add them). Try two coins: you get HH, HT, TH and TT. HT and TH are different outcomes, because "first coin heads, second tails" is not the same as the other way round. Imagine one coin is a 10p and the other a 2p and it's obvious.

3 · Sample space diagrams: two dice

Roll two dice. Listing 36 pairs is slow, so we draw a sample space diagram: a grid with Dice 1 down the side and Dice 2 along the top. Each of the 36 cells is one equally likely outcome. In each cell we write whatever we care about: the sum (add), the difference (bigger take away smaller) or the product (multiply).

To find a probability, count the cells in your event and put that number over 36. Tap any cell to highlight every cell with the same value, or build an event with the menus.

Event
Cells
Probability

Look at the sums: 7 appears 6 times (a whole diagonal) but 2 and 12 appear only once each. That's why 7 is the most common total with two dice. There are 11 different totals, but they are not equally likely, so P(total is 7) is not 1/11. Always count the 36 cells.

4 · Two-way tables

A two-way table sorts a group of people (or things) in two different ways at once: one way across the rows, the other down the columns. Here, a group of students is split by boys and girls (rows) and by how they get to school (columns). The Total row and column add things up:

So if one number in a row or column is missing and you know all the others, you can always find it by adding or subtracting. Fill in the gaps below and press Check. If you're stuck, the feedback points you to a row or column with just one gap.

When a question says "a student is picked at random from the group", the bottom of the fraction is the grand total. When it says "a girl is picked at random", you are only choosing from the girls, so the bottom is the girls' total. Read who is being picked! (If the table came from a survey, these probabilities are really estimates: see theoretical and experimental probability.)

5 · Venn diagrams: ξ, ∩, ∪ and ′

A set is a collection of things, called its elements, written in curly brackets. For example, if A is "even numbers up to 10" then A = {2, 4, 6, 8, 10}. We write n(A) for how many elements are in A, so n(A) = 5.

A Venn diagram draws sets as circles inside a rectangle. The rectangle is the universal set, written ξ (the Greek letter "xi", said "ksy"): everything we are talking about. Here ξ = {1, 2, 3, …, 20}. Each number goes in exactly one region:

SymbolSay itMeans
A ∩ BA intersection Bin A and in B: the overlap in the middle
A ∪ BA union Bin A or B or both: anywhere inside the circles
A′A complement / not Anot in A: everything outside circle A, including outside both circles

A memory trick: ∩ looks like a bridge between the circles ("and"); ∪ is a cup that holds everything ("or"). Drag each number into the region where it belongs. If you put one in the wrong place, you'll be told why. Then tap a button (or a region) to shade it and see its probability if one of the 20 numbers is picked at random.

Region
Elements
Probability

Not A, A′, includes the outside. Numbers outside both circles are still in ξ, so they belong to A′. Also, every number is either in A or in A′, never both, so P(A) + P(A′) = 1. That idea is the main topic of mutually exclusive outcomes.

6 · Filling in a Venn diagram from numbers

Often you aren't given the elements, just how many there are, like this: "30 students: 18 play football, 12 play tennis, 5 play both." Now each region holds a frequency (a count). The golden rule is start in the middle:

  1. Put the "both" number in the overlap.
  2. The 18 football players include the 5 who play both, so football only = 18 − 5 = 13.
  3. Tennis only = 12 − 5 = 7.
  4. Outside both = 30 − (13 + 5 + 7) = 30 − 25 = 5. Don't forget this region!

Your turn. Fill in all four regions and press Check, or press Show me step by step to watch it done.

Once the diagram is full, probabilities are easy: add up the regions you want and divide by the total in ξ. For "or" (∪) add all three regions inside the circles once each; for "not" (′) remember the region outside both circles.

7 · Spot the mistake

Each of these students has made one of the classic mistakes. Read their work and pick what went wrong.

Common mistakes to avoid

Worked examples

A spinner (red, blue, green) is spun and a coin is flipped. List the outcomes and find P(blue and heads).
Fix the spinner, run through the coin: (R, H), (R, T), then (B, H), (B, T), then (G, H), (G, T).
Count: 6 outcomes. Check: 3 spinner outcomes × 2 coin outcomes = 6 ✓.
Event "blue and heads": only (B, H), so 1 outcome.
Probability: P(blue and heads) = 1/6.
Bonus: P(heads) = 3/6 = 1/2, since (R, H), (B, H) and (G, H) all have heads.
Two dice are rolled and the scores added. Find P(sum is 8), P(sum more than 9) and P(a double).
Sample space: 6 × 6 = 36 equally likely cells.
Sum is 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) → 5 cells. P = 5/36.
Sum more than 9 means 10, 11 or 12. Sum 10: (4, 6), (5, 5), (6, 4) → 3. Sum 11: (5, 6), (6, 5) → 2. Sum 12: (6, 6) → 1. Total 3 + 2 + 1 = 6 cells. P = 6/36 = 1/6.
A double: (1, 1), (2, 2), …, (6, 6) → 6 cells (the diagonal). P = 6/36 = 1/6.
Complete the two-way table, then find some probabilities.
WalkBusCarTotal
Boys12?828
Girls?9??
Total25?1860
Boys row: 12 + ? + 8 = 28, so boys by bus = 28 − 12 − 8 = 8.
Walk column: 12 + ? = 25, so girls who walk = 25 − 12 = 13.
Car column: 8 + ? = 18, so girls by car = 18 − 8 = 10.
Total column: 28 + ? = 60, so girls' total = 60 − 28 = 32. Check the girls' row: 13 + 9 + 10 = 32 ✓.
Bus column: 8 + 9 = 17. Check the totals row: 25 + 17 + 18 = 60 ✓.
A student is picked at random. P(a girl who walks) = 13/60. P(comes by bus) = 17/60.
A girl is picked at random. Now we choose only from the 32 girls: P(she comes by car) = 10/32 = 5/16.
30 students: 18 play football (F), 12 play tennis (T), 5 play both. Draw the Venn diagram and find P(neither), P(F ∪ T) and P(exactly one sport).
Middle first: F ∩ T = 5.
F only: 18 − 5 = 13. T only: 12 − 5 = 7.
Outside: 13 + 5 + 7 = 25 are inside the circles, so 30 − 25 = 5 play neither.
P(neither) = 5/30 = 1/6.
P(F ∪ T) = (13 + 5 + 7)/30 = 25/30 = 5/6. (Not (18 + 12)/30: that counts the 5 twice.)
P(exactly one sport) = (13 + 7)/30 = 20/30 = 2/3.
ξ = {1, 2, …, 12}, A = multiples of 2, B = multiples of 3. Find A ∩ B, A ∪ B, A′ and their probabilities.
List the sets: A = {2, 4, 6, 8, 10, 12}, B = {3, 6, 9, 12}.
A ∩ B (in both) = {6, 12}. P(A ∩ B) = 2/12 = 1/6.
A ∪ B (in either) = {2, 3, 4, 6, 8, 9, 10, 12}, 8 numbers. P(A ∪ B) = 8/12 = 2/3. Check: 6 + 4 − 2 = 8, because 6 and 12 would otherwise be counted twice ✓.
A′ (not in A) = {1, 3, 5, 7, 9, 11}. P(A′) = 6/12 = 1/2. Check: P(A) + P(A′) = 6/12 + 6/12 = 1 ✓.
Outside both circles: {1, 5, 7, 11}. These are in A′ and in B′.

Quick check

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